Q: What is the total or count of factors of the number 2,022,935?

A: 12

How do I find the total factors of the number 2,022,935?

Step 1

Find the prime factorization of the number 2,022,935.

Use a factor tree to assist with solving. Take a look at our prime factorization page for additional help.

Factor Tree

	2,022,935

5		404,587

	43		9,409

		97		97

The prime factorization in exponential form is: 5¹ x 43¹ x 97²

Step 2

Setup the equation for determining the number of factors or divisors. The equation is:

d(n) = (a + 1)(b + 1)(c + 1)

Where d(n) is equal to the number of divisors of the number and a, b, etc. are equal to the exponents of the prime factorization.

Now substitute the letters in the equation with the the exponents of your prime factorization and then solve to calculate the total number of divisors.

2,022,935 = 5¹ x 43¹ x 97²

d(n) = (a + 1)(b + 1)(c + 1)

d(2022935) = (1 + 1)(1 + 1)(2 + 1)

d(2022935) = (2)(2)(3)

d(2022935) = 12

More numbers for you to try

Take a look at the factors page to see the factors of 2,022,935 and how to find them.

Try the factor calculator.

Explore more about the number 2,022,935:

General Questions

Factoring Questions

Calculation Questions