Q: What is the total or count of factors of the number 242,020,108?

A: 48

How do I find the total factors of the number 242,020,108?

Step 1

Find the prime factorization of the number 242,020,108.

Use a factor tree to assist with solving. Take a look at our prime factorization page for additional help.

Factor Tree

	242,020,108

2		121,010,054

	2		60,505,027

		11		5,500,457

			37		148,661

				47		3,163

The prime factorization in exponential form is: 2² x 11¹ x 37¹ x 47¹ x 3,163¹

Step 2

Setup the equation for determining the number of factors or divisors. The equation is:

d(n) = (a + 1)(b + 1)(c + 1)(d + 1)(e + 1)

Where d(n) is equal to the number of divisors of the number and a, b, etc. are equal to the exponents of the prime factorization.

Now substitute the letters in the equation with the the exponents of your prime factorization and then solve to calculate the total number of divisors.

242,020,108 = 2² x 11¹ x 37¹ x 47¹ x 3,163¹

d(n) = (a + 1)(b + 1)(c + 1)(d + 1)(e + 1)

d(242020108) = (2 + 1)(1 + 1)(1 + 1)(1 + 1)(1 + 1)

d(242020108) = (3)(2)(2)(2)(2)

d(242020108) = 48

More numbers for you to try

Take a look at the factors page to see the factors of 242,020,108 and how to find them.

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