Q: What is the total or count of factors of the number 4,244,535?

 A: 32

How do I find the total factors of the number 4,244,535?

Step 1

Find the prime factorization of the number 4,244,535.

Use a factor tree to assist with solving. Take a look at our prime factorization page for additional help.

Factor Tree
4,244,535
Factor Arrows
31,414,845
Factor Arrows
3471,615
Factor Arrows
3157,205
Factor Arrows
531,441
Factor Arrows
231,367

The prime factorization in exponential form is: 33 x 51 x 231 x 1,3671

Step 2

Setup the equation for determining the number of factors or divisors. The equation is:

d(n) = (a + 1)(b + 1)(c + 1)(d + 1)

Where d(n) is equal to the number of divisors of the number and a, b, etc. are equal to the exponents of the prime factorization.

Now substitute the letters in the equation with the the exponents of your prime factorization and then solve to calculate the total number of divisors.

4,244,535 = 33 x 51 x 231 x 1,3671
Down Arrow
d(n) = (a + 1)(b + 1)(c + 1)(d + 1)
Down Arrow
d(4244535) = (3 + 1)(1 + 1)(1 + 1)(1 + 1)
Down Arrow
d(4244535) = (4)(2)(2)(2)
Down Arrow
d(4244535) = 32

More numbers for you to try

Take a look at the factors page to see the factors of 4,244,535 and how to find them.

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