Q: What is the total or count of factors of the number 430,340,120?

A: 128

How do I find the total factors of the number 430,340,120?

Step 1

Find the prime factorization of the number 430,340,120.

Use a factor tree to assist with solving. Take a look at our prime factorization page for additional help.

Factor Tree

	430,340,120

2		215,170,060

	2		107,585,030

		2		53,792,515

			5		10,758,503

				7		1,536,929

					19		80,891

						23		3,517

The prime factorization in exponential form is: 2³ x 5¹ x 7¹ x 19¹ x 23¹ x 3,517¹

Step 2

Setup the equation for determining the number of factors or divisors. The equation is:

d(n) = (a + 1)(b + 1)(c + 1)(d + 1)(e + 1)(f + 1)

Where d(n) is equal to the number of divisors of the number and a, b, etc. are equal to the exponents of the prime factorization.

Now substitute the letters in the equation with the the exponents of your prime factorization and then solve to calculate the total number of divisors.

430,340,120 = 2³ x 5¹ x 7¹ x 19¹ x 23¹ x 3,517¹

d(n) = (a + 1)(b + 1)(c + 1)(d + 1)(e + 1)(f + 1)

d(430340120) = (3 + 1)(1 + 1)(1 + 1)(1 + 1)(1 + 1)(1 + 1)

d(430340120) = (4)(2)(2)(2)(2)(2)

d(430340120) = 128

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Take a look at the factors page to see the factors of 430,340,120 and how to find them.

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