Q: What is the total number of prime factors of the number 740,936?
A: 6
First, you must factor the number. Then, you must identify the prime numbers. Finally, you then count the number of prime factors.
In the case of the number 740,936, the prime factors are: 2, 2, 2, 7, 101, 131 or also written as { 2, 2, 2, 7, 101, 131 }
If you would like to know more, or need additional explanation, please review our prime factorization explanation.